A shopper in a supermarket pushes a cart with a force of 38 N directed at an angle of 24 degree downward from the horizontal.
Find the work done by the shopper on the cart as the shopper moves along a 51.7 m length of aisle.
Answer in units of J.
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The work done by the shopper by his pushing force is equal to the product of force times the distance along the direction of force = 38N*51.7m
Force applied on cart = ft = 38 N
Angle of application of force = A = 24 degrees downward to horizontal.
Distance moved = s = 51.7 m
The force applied is not in horizontal. Therefore the whole force is not used for pushing the cart.
The force used for pushing the cart (fh) is only the horizontal component of the total force applied.
We know: fh = fh*Cos A = 38*Cos 24 = 38*0.9135 = 34.713
Work done = force*distance = 34.713*51.7 = 1794.6621 J
Answer: Work dione on the cart is 1794.6621 J.
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