a set of data is normally distributed w / a mean of 500 & standard d of 100 what % of scores is between 500 & 300, and what would be the percentile rank for a score of 300please show work
We are given a normally distributed set with `bar(x)=500` and `s=100`
(a) The percentage of scores between 300-500:
Convert 300 and 500 to standard `z` scores:
`500: z=(500-500)/100=0` (Naturally!)
The percentage of scores between 300 and 500 is the probability of getting a `z` score between -2 and 0
`P(300<x<500)=P(-2<z<0)` From a standard normal table we find the probability that a `z` score is less than -2 to be .0228, and the probability that a score is less than 0 to be .5 (Naturally!)
So `P(-2<z<0)=.5-.0228=.4772` or approximately 47.7% of the scores will lie between 300 and 500.
(Using a graphing calculator I got .4772499385)
(b) The percentile score for 300 is the percentage of scores less than 300.
`P(x<300)=P(z<-2)=.0228` as found in (a), so the percentile for 300 is approximately the 2nd percentile.