`(sec(theta) - 1)/(1 - cos(theta)) = sec(theta)` Verfiy the identity.

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Chapter 5, 5.2 - Problem 24 - Precalculus (3rd Edition, Ron Larson).
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mathace | (Level 3) Assistant Educator

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Verify the identity: `[sec(theta)-1]/[1-cos(theta)]=sec(theta)`

Use the reciprocal identity `cos(theta)=1/sec(theta)`

`[sec(theta)-1]/[1-cos(theta)]=sec(theta)`

`[sec(theta)-1]/[1-(1/sec(theta))]=sec(theta)`

`[sec(theta)-1]/[[sec(theta)-1]/sec(theta)]=sec(theta)` 

`[sec(theta)-1]*sec(theta)/[sec(theta)-1]=sec(theta)`

`sec(theta)=sec(theta)` 

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