`sec(pi)` Evaluate the trigonometric function of the quadrant angle, if possible.

Textbook Question

Chapter 4, 4.4 - Problem 40 - Precalculus (3rd Edition, Ron Larson).
See all solutions for this textbook.

1 Answer | Add Yours

kspcr111's profile picture

kspcr111 | In Training Educator

Posted on

`sec(pi) = 1 /cos(pi)= 1/cos(pi+0)`

As,`cos (pi +x) = -cos(x)`

so `cos(pi+0)= -cos(0) = -1`

Therefore

`sec(pi) = 1/cos(pi+0) = 1/(-1) = -1`

We’ve answered 318,957 questions. We can answer yours, too.

Ask a question