# `sec(pi)` Evaluate the trigonometric function of the quadrant angle, if possible.

*print*Print*list*Cite

Student Comments

kspcr111 | Student

`sec(pi) = 1 /cos(pi)= 1/cos(pi+0)`

As,`cos (pi +x) = -cos(x)`

so `cos(pi+0)= -cos(0) = -1`

**Therefore**

`sec(pi) = 1/cos(pi+0) = 1/(-1) = -1`