`sec(arctan(-3/5))` Find the exact value of the expression. (Hint: Sketch a right triangle.)

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Chapter 4, 4.7 - Problem 59 - Precalculus (3rd Edition, Ron Larson).
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balajia | College Teacher | (Level 1) eNoter

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`tan^-1(-3/5) = -tan^-1(3/5)`

Taking 3 as opposite side and 5 as adjacent side , then the hypotenuse will be `sqrt(5^2+3^2)=sqrt(34).`


`sec(tan^-1(-3/5)) = sec(-tan^-1(3/5))`



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