`sec^2 (x) - 1 = 0` Find all the solutions of the equation in the interval `0,2pi)`.

Textbook Question

Chapter 5, 5.3 - Problem 26 - Precalculus (3rd Edition, Ron Larson).
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mathace | (Level 3) Assistant Educator

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Solve: `sec^2(x)-1=0,[0,2pi)`

`tan^2(x)=1` ` `

`tan(x)=+-sqrt(1)`

`tan(x)=+-1`

`x=pi/4,x=(3pi)/4,x=(5pi)/4,x=(7pi)/4` 

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