A saturated solution of KClO3 (s) was made with 300 grams of water at 40 degrees Celsius. How much KClO3 (s) could be recovered if the solution was evaporated to dryness? 0 degrees Celsius - 5 g/100 mL 10 degrees Celsius - 6 g/100 mL 20 degree Celsius - 9 g/100 mL 30 degree Celsius - 12 g/100 mL 40 degrees Celsius - 18 g/100 mL ^ Quantity of solute needed to make a saturated solution in 100 grams of water at that temperature. PLEASE HELP!

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If we make a saturated solution, then the maximum amount of solute is dissolved in it and no more.  Any additional solute added will result in precipitation of the solute. 

If we have a solution at 40 degC, then we can have 18g KClO3 per 100 mL of water.  We...

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If we make a saturated solution, then the maximum amount of solute is dissolved in it and no more.  Any additional solute added will result in precipitation of the solute. 

If we have a solution at 40 degC, then we can have 18g KClO3 per 100 mL of water.  We can assume that the density of water is 1.00 g/mL over this temperature range so if we have 300 g of water, that would be the same as having 300 mL of water.

So for 300 mL of water, we can dissolve 3 * 18 g of KClO3 in the water and have 54 g KClO3 dissolved.  If the sample is allowed to evaporate to dryness at this temperature, then theoretically we could recover 54 g of KClO3. 

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