If a signal from the satellite travels at 3*10^8 m/s, how long does it take to reach the dish? Radius of the earth is 6370 km. A satellite is in an orbit 1000 km above the surface of the earth. A recieving dish is located so that the directions from satellite to the dish and from the satellite to the centre of the earth make an angle of 27 degrees.

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The satellite is in orbit 1000 km above the surface of the Earth. If a line is drawn from the satellite to the receiving dish it makes an angle of 27 degrees with the vertical drawn from the satellite to the center of the Earth.

As the satellite is 1000...

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The satellite is in orbit 1000 km above the surface of the Earth. If a line is drawn from the satellite to the receiving dish it makes an angle of 27 degrees with the vertical drawn from the satellite to the center of the Earth.

As the satellite is 1000 km above the surface, the distance of the satellite from the center of the Earth is 7370 km. The distance of the satellite from the dish is equal to `7370/(cos 27)= 8271.54` km. The time taken by a signal traveling at `3*10^8` m/s is equal to `(8271.54*10^3)/(3*10^8) = 0.027` seconds.

The signal takes approximately 0.027 seconds to travel from the satellite to the dish.

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