A sample of oxygen collected over water at32C and 1038 torr has a volume of 0.741 L. What volume would the dry oxygen occupyunder standard conditions?The vapor pres-sure of water at 32C is 35.7...

A sample of oxygen collected over water at
32C and 1038 torr has a volume of 0.741 L.

What volume would the dry oxygen occupy
under standard conditions?The vapor pres-
sure of water at 32C is 35.7 torr.
Answer in units of L

Asked on by paadms214

1 Answer | Add Yours

jerichorayel's profile pic

jerichorayel | College Teacher | (Level 2) Senior Educator

Posted on

Hello!

This problem can be solved using the combined gas law equation.

P1V1/T1 = P2V2/T2

 

***The key to this type of problem is to let the units be the same for the 1's and 2's.

*** at standard condition, T is 273.15 and P is 1atm or 760 torr

P1 = 1038 torr                          P2 = 760 torr

T1 = 32 + 273.15 = 305.15K    T2 = 273.15 K

V1 = 0.741L                              V2 = ?

 

applying the formula above, substitue the values given.

 

(1038)(0.741)/ 305.15 = (760)(V2)/(273.15)

 

V2 = 0.906 L



hope this helps :)

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