A sample of ideal gas at room temperature occupies a volume of 17.0L at a pressure of 822torr . If the pressure changes to 4110torr , with no change in the temperature or moles of gas, what is the new volume, V2?

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We can use the Boyle’s law in order to solve the problem. We know that pressure is inversely proportional to the volume of the gas. Having said that, the expression can be written as:

`(P_1)*(V_1) = (P_2)*(V_2) `

Where:

`P_1` = 822 Torr

`P_2` = 4110 Torr

`V_1` = 17.0...

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We can use the Boyle’s law in order to solve the problem. We know that pressure is inversely proportional to the volume of the gas. Having said that, the expression can be written as:

`(P_1)*(V_1) = (P_2)*(V_2) `

Where:

`P_1` = 822 Torr

`P_2` = 4110 Torr

`V_1` = 17.0 L

`V_2` = ?

Substitute the values and solve for `V_2`

`(P_1)*(V_1) = (P_2)*(V_2)`

`V_2 = (P_1*V_1)/(P_2) `

`V_2 = (822*17.0)/(4110) `

`V_2 = 3.40 L` -> answer

The final volume (`V_2` ) should decrease because the applied pressure (`P_2` ) increases. 

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