A sample of gas has a volume of 2.4 L. Determine the new volume of the gas if the pressure is halved?  

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The ideal gas law gives P*V = n*R*T, where P is the pressure on the gas, V is the volume of the gas, n is the number of moles, R is a constant and T is the temperature.

Here the volume of the gas is initially 2.4 l, we need...

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The ideal gas law gives P*V = n*R*T, where P is the pressure on the gas, V is the volume of the gas, n is the number of moles, R is a constant and T is the temperature.

Here the volume of the gas is initially 2.4 l, we need to find the volume when the pressure is reduced to half. I assume the temperature is the same.

So pressure and volume are inversely proportional. We can write this as P = k/V.

P = k/2.4

=> k = 2.4 P

P/2 = k/ V

=> P/2 = 2.4* P/ V

=> V = (2.4*P)/(P/2)

=> V = 2.4*2

=> V = 4.8

The volume of the gas when the pressure is reduced to half is 4.8 L.

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