Sales for a business were 3 million dollars more the second year than the first, and sales for the third year were double the sales for the second year. If sales for the third year were 38 million dollars, what were sales, in millions of dollars, for the first year

Expert Answers

Let the sales of first year be x,

second year sales are 3 million more than the first year i.e, `x + 3 ` (assume 1 million as 1)

and third year sales are double the second year sales i.e, `2(x +3) ` which is equal to 38 millions.

`2(x +3) = 38`

`x+3 = 38/2 = 19`

`x = 19 - 3 = 16`

`therefore` I year sales are 16 millions, II year  sales are 19 millions and III year  sales are 38 millions sales.

Approved by eNotes Editorial Team

Year 2 sales were 3 million more than year 1 sales, and year 3 sales were double year 2 sales. If year 3 sales were 38 million, what were sales in year 1?

Let x be year 1 sales. Then year 2 sales are x+3, and year 3 sales are 2x+6.

2x+6=38 ==> 2x=32 ==> x=16

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Year 1 sales were 16 million.

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Year 1 sales are 16 million, so year 2 sales are 19 million (3 million more), and year 3 sales are 38 million (twice 19 is 38.)

Approved by eNotes Editorial Team

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