Let the sales of first year be x,

second year sales are 3 million more than the first year i.e, `x + 3 ` (assume 1 million as 1)

and third year sales are double the second year sales i.e, `2(x +3) ` which is equal to 38 millions.

`2(x +3) = 38`

`x+3 = 38/2 = 19`

`x = 19 - 3 = 16`

`therefore` I year sales are 16 millions, II year sales are 19 millions and III year sales are 38 millions sales.

Year 2 sales were 3 million more than year 1 sales, and year 3 sales were double year 2 sales. If year 3 sales were 38 million, what were sales in year 1?

Let x be year 1 sales. Then year 2 sales are x+3, and year 3 sales are 2x+6.

2x+6=38 ==> 2x=32 ==> x=16

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**Year 1 sales were 16 million.**

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Year 1 sales are 16 million, so year 2 sales are 19 million (3 million more), and year 3 sales are 38 million (twice 19 is 38.)

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