A rope pulls a 2.0 kg bucket straight up, accelerating it from rest at 2.2 m/s^2 for 3.0 s.
1. Calculate the work done by each force acting on the bucket?
2. Calculate the net force acting on the bucket and the work done by the net force?
The rope pulls the 2.0 kg buckets vertically upwards accelerating it from rest at 2.2 m/s^2 for 3 seconds.
In 3 seconds, the distance traveled by the bucket is equal to s = u*t + (1/2)*a*t^2. Here u = 0, t = 3 and a = 2.2
This gives s = (1/2)*2.2*9 = 9.9 m
There are two forces acting on the bucket, one of them is the force accelerating it upwards at a net acceleration of 2.2 m/s^2 and the other is the gravitational force of attraction of the Earth that is equal to 9.8 m/s^2 and acts in the downward direction.
The work done by a force F that acts over a distance d is equal to W = F*d = m*a*d.
The net work done by the upward acting force applied by the rope is (9.8+2.2)*2*9.9 = 237.6 J and the work done by the force of gravity is 9.8*2*9.9 = 194.04 J