The equation of motion

s= ut + 1/2 at^2

can be used to solve this question. In this equation, s is the distance traveled, u is the initial velocity, t is the time taken and a is the acceleration.

Since, the rock is dropped, the initial velocity of the rock...

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The equation of motion

s= ut + 1/2 at^2

can be used to solve this question. In this equation, s is the distance traveled, u is the initial velocity, t is the time taken and a is the acceleration.

Since, the rock is dropped, the initial velocity of the rock is 0 m/s. That is,

u = 0 m/s

The acceleration of the rock would be equal to the acceleration due to gravity, g. The value of g (approximately) 9.81 m/s^2 or 32.2 ft/s^2.

And, time taken for the rock to hit the ground, t = 3 s.

Substituting the values of u, t and a in the equation, we get:

s = 0 x 3 + 1/2 x 32.2 x 3^2 = **144.9 ft**.

Thus, the rock dropped from the window will travel a distance of about 144.9 ft before hitting the ground.

Hope this helps.