A right circular cone is generated by revolving the region bounded by `y=3x/4, y=3, x=0` about the y-axis. Find the lateral surface area of the cone.

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Surface area (S) obtained by rotating the curve x=g(y), c `<=`  y `<=` d about y-axis is,


 where, ds=`sqrt(1+(dx/dy)^2)dy`

We are given `y=(3x)/4 , y=3 , x=0`













So the Lateral surface area of the cone is `20pi`


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