We have the right triangle ABC where AC is the hypotenuse and AB= 6 and BC = 8.

By the Pythagorean theorem: AC^2 = AB^2 + BC^2

=> AC^2 = 6^2 + 8^2

=> AC = sqrt [ 36 + 64]

=> AC = sqrt 100

=> AC = 10

Now **sin A = 8/10 = 4/5**

**cos A = 6/10 = 3/5**

and **tan A = 8/6 = 4/3**

Given the the...

(The entire section contains 2 answers and 128 words.)

## Unlock This Answer Now

Start your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.