The right angled triangle ABC has AB=6, BC=8 and AC is the hypotenuse. Find sinA, cosA and tanA.

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We have the right triangle ABC where AC is the hypotenuse and AB=  6 and BC = 8.

By the Pythagorean theorem: AC^2 = AB^2 + BC^2

=> AC^2 = 6^2 + 8^2

=> AC = sqrt [ 36 + 64]

=> AC = sqrt 100

=> AC = 10

Now sin A = 8/10 = 4/5

cos A = 6/10 = 3/5

and tan A = 8/6 = 4/3

Given the the...

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