Rewrite the quadratic equation in standard form by completing the square. `f(x)=-(1/3)x^2+6x+6`

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embizze | High School Teacher | (Level 2) Educator Emeritus

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`f(x)=-1/3x^2+6x+6`

`=-1/3[x^2-18x-18]`  We need a leading coefficient of 1

`=-1/3[x^2-18x+81-81-18]` Add/subtract  1/2 "b" squared

`=-1/3[(x-9)^2-99]` Rewrite trinomial as binomial squared

`=-1/3(x-9)^2+33` Distribute the -1/3

Thus the solution is `f(x)=-1/3(x-9)^2+33`