A reuters/zogby poll showed that 61% of americans say they believe that life exists somewhere else in the galaxy. What is the probability of randomly selecting someone not having that belief?

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sociality | High School Teacher | (Level 1) Valedictorian

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We are given the percentage of Americans who believe that life exists somewhere else in the galaxy is 61%. So 61 out of every 100 people polled believe that life exists somewhere else in the galaxy.

Therefore (100 - 61) = 39 out of 100 Americans do not believe that life exists somewhere else in the galaxy.

Therefore, if we need to find the probability of people who do not believe we have 39 favorable events for every 100 events.

Therefore the required probability is 39%.

The probability of randomly selecting someone who does not believe that life exists somewhere else in the galaxy is 39%.

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neela | High School Teacher | (Level 3) Valedictorian

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If p is the probability of an American selected randomly believing life existing somewhere else in the galaxy, then 1-p is the probability that an American not believing that life exists somehere else in the galaxy.

Given the probability of this belief p = 0.61 according to the poll conducted by zogby.

So it implies that any randomly slected American is not a believer in life existing somewhere else in the galaxy is 1-p = 1-0.61 = 0.39.

 

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