# a rectangular tank has a lenght of 0.6meters, a width of 0.35 meters and its height is 15 cm and it is full of water. this water is then poured into a cylindrical container which has the capacity of 50 litres and the height of the cylinder is 0.7 meters. what is the depth of the water in the cylinder.

Compute the volume of water in the rectangular tank:

V=LxWxH

Substitute 0.6 m for L, 0.35 m for width and 0.015 m for height.

`V=(0.6m)(0.35m)(0.15m)=0.0315m^3`

Thus the volume of the rectangular tank is 0.0315 cubic meters.

Convert the volume of the cylindrical container from litres to `m^3`

(1 liter=0.001 cubic meters)

`V=(50 l)(0.001 m^3/l)=0.05m^3`

Thus the volume of the cylindrical container is 0.05 cubic meters.

Compute the base area A of the cylindrical container:

V=AxH or A=V/H

Substitute 0.05`m^3` for volume and 0.7 m for height H.

`A=(0.05m^3)/(0.7m)=0.07m^2`

Compute the height of water in the cylindrical container using

H=V/A

Substitute the volume of water 0.0315`m^3` for V and 0.07`m^2` for A.

`H=(0.0315m^3)/(0.07m^2)=0.45m`

Thus the depth of the water in the cylindrical container is 0.45m.

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