# a rectangular tank has a lenght of 0.6meters, a width of 0.35 meters and its height is 15 cm and it is full of water. this water is then poured into a cylindrical container which has the capacity...

a rectangular tank has a lenght of 0.6meters, a width of 0.35 meters and its height is 15 cm and it is full of water. this water is then poured into a cylindrical container which has the capacity of 50 litres and the height of the cylinder is 0.7 meters. what is the depth of the water in the cylinder.

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Compute the volume of water in the rectangular tank:

V=LxWxH

Substitute 0.6 m for L, 0.35 m for width and 0.015 m for height.

`V=(0.6m)(0.35m)(0.15m)=0.0315m^3`

**Thus the volume of the rectangular tank is 0.0315 cubic meters.**

Convert the volume of the cylindrical container from litres to `m^3`

(1 liter=0.001 cubic meters)

`V=(50 l)(0.001 m^3/l)=0.05m^3`

**Thus the volume of the cylindrical container is 0.05 cubic meters.**

Compute the base area A of the cylindrical container:

V=AxH or A=V/H

Substitute 0.05`m^3` for volume and 0.7 m for height H.

`A=(0.05m^3)/(0.7m)=0.07m^2`

Compute the height of water in the cylindrical container using

H=V/A

Substitute the volume of water 0.0315`m^3` for V and 0.07`m^2` for A.

`H=(0.0315m^3)/(0.07m^2)=0.45m`

**Thus the depth of the water in the cylindrical container is 0.45m.**

The volume of the tank is 0.0315 cubic metres, the volume of the container is 0.05 cubic metres and the depth of the water is the container is 0.45m.