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A rectangular parking lot has perimeter of 120 meters and area 875 square meters. What are the dimensions of the parking lot:
(1)Let the perimeter P=2l+2w where l is the length and w is the width. So 120=2l+2w and 2w=120-2l or w=60-l.
(2) The area is A=lw=l(60-l). Then 875=l(60-l). Thus:
`l=25` or `l=35` .
If l=25 then w=35, and if l=35 then w=25.
(3) The dimensions of the parking lot are 35m x 25m
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