A rectangular floor that has the length L = 9m and the width l = 3m must be covered with tiles with square shape and length of the side = 30 cm . Which is the necessary number of tiles ?
- print Print
- list Cite
Expert Answers
calendarEducator since 2008
write3,662 answers
starTop subjects are Math, Science, and Social Sciences
First we need to calculate the area of the floor
Since it is a rectangulal floor, then the area to be covered is L*I= 9*3=27 m ^2
=270,000 cm^2
Now we need to cover the area with (n) numbers of square each with 30 cm side:
Then the area of the square is 30*30=900 cm^2
Then 900*n = 270,000
==> n =300 tiles
Then we need 300 square tiles to cover the area.
Related Questions
- A rectangular floor measures 3m by 2m is covered by 384 square tiles. Determine the side length...
- 1 Educator Answer
- The length l of a rectangle is decreasing at the rate of 2 cm/sec while the width w is increasing...
- 1 Educator Answer
- The length and width of a rectangle are in the ration 5:3.. perimeter is 32 cm. Find length and...
- 1 Educator Answer
- What is the length of the longest stick that can be placed in a rectangular box with dimensions 6...
- 2 Educator Answers
- Related rates problem: The length of a rectangle is increasing at a rate of 8 cm/s and its width...
- 2 Educator Answers
Since two units are given we must first convert the different units into one uniform unit. So,
30cm = 30/100 m = 0.3m
Next in order to find out the number of tiles required to cover the entire floor, we must calculate the area of the entire floor. We can do this by multiplying L x l = 27 square metres.
Next we have to find the area of the square tile. We do this by multiplying its length and breadth:
.3 x .3 = .9 sq.ms.
To find out the number of tiles required to cover the entire floor we have to divide the area of the entire floor 27 sq.ms. by the area of one tile .9 sq.ms
27 / .9 = 270 / 9 = 300 tiles.
Answer = 300 tiles
Given:
Length of floor = L = 9 m
Width of room = l = 3 m
Length of sides of square tiles = t = 30 cm = 0.3 m
Therefore:
Area of the floor = A = L x l = 9x3 = 27 m^2
Area of one tile = a = t^2 = 0.3^2 = 0.09 m^2
Number of tiles required = (Area of floor)/(area of one tile)
= 27/0.09 = 300
Answer:
300 tile are required to cover the floor.
Length of the rectangular shape = 9m or 9oo cm and the width is 3m or 300 cm
Threfore we can arrange 900/30 = 30 tiles of 30 cm by 30 cm squares along the length.
Along the width we can arrange 300/30 = 10 tiles.
So The entire rectangular area could be covered by 30*10 = 300 tiles..
In order to find out the number of needed tiles to cover the length and the width of the floor, first we have to do the conversions from centimeter (cm) unit of measure to the meter (m) unit of measure.
30cm = 30/100 m = 0.3m
The number of tiles which will cover the length L will be: 9/0.3 = 30 tiles
The number of tiles which will cover the width w will be:
3/0.3 = 10 tiles
In order to find out how many tiles are needed to cover the entire rectangular surface of the wall, we must calculate the area of the floor, using the number of tiles found above:
A = L*w = 30x10 = 300 tiles.
Student Answers