Rectangular doghouses come in two sizes at the super z. The smaller size is 2 feet by 1 feet. The larger size is 4 feet by 2 feet. How many square feet greater is the larger doghouse?
To solve, let's compute the area of each doghouse. Apply the
formula of area of rectangle which is:
So, the area of the smaller doghouse is:
And the area of the larger doghouse is:
Then, get the difference of the areas.
`A_L - A_s= 8-2 = 6`
Hence, the larger doghouse is 6 square feet greater than the smaller doghouse.