Rectangular doghouses come in two sizes at the super z. The smaller size is 2 feet by 1 feet. The larger size is 4 feet by 2 feet. How many square feet greater is the larger doghouse?

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To solve, let's compute the area of each doghouse. Apply the formula of area of rectangle which is:`A=lxxw` So, the area of the smaller doghouse is:`A_S=2 xx1` `A_S=2` And the area of the larger doghouse is:`A_L=4xx2` `A_L=8` Then, get the difference of the areas. `A_L - A_s=...

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To solve, let's compute the area of each doghouse. Apply the
formula of area of rectangle which is:

`A=lxxw`

So, the area of the smaller doghouse is:

`A_S=2 xx1`

`A_S=2`

And the area of the larger doghouse is:

`A_L=4xx2`

`A_L=8`

Then, get the difference of the areas.

`A_L - A_s= 8-2 = 6`

Hence, the larger doghouse is 6 square feet greater than the smaller doghouse.

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