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To solve, let's compute the area of each doghouse. Apply the
formula of area of rectangle which is:
So, the area of the smaller doghouse is:
And the area of the larger doghouse is:
Then, get the difference of the areas.
`A_L - A_s= 8-2 = 6`
Hence, the larger doghouse is 6 square feet greater than the smaller doghouse.
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