A rectangle with a perimeter of 30 centimeters is twice as long as it is wide. What is the area of the rectangle in square centimeters?
Given that the perimeter of a rectangle is 30 cm.
We will assume that the length = L and the width = W
==> 2w + 2L = 30
==> L + w = 15 ...............(1)
Now, given that the length if twice the width.
==> L = 2w
Now we will substitute onto (2).
==> 2w + w = 15
==> 3w = 15
We will divide by 3.
==> w = 5
==> L = 2*5 = 10
Now we will calculate the area.
==> A = L*w = 10*5 = 50
Then, the area of the rectangle is 50 cm^2
The rectangle has a perimeter of 30 cm. Its length is twice its width. Let us denote length by L and width by W.
So we have L = 2W
Perimeter = 2L + 2W = 30
=> 2* 2W + 2W = 30
=> 4W + 2W = 30
=> 6W = 30
=> W = 5
L = 10
The area = L*W = 5* 10 = 50
Therefore the area of the rectangle is 50 cm^2.
Let length =2X=2X5CM.=10cm To obviously find area of a
let width= X=5CM. rectangle we then multiply the
2x+x+2x+x=30 CM Length and Width
6x=30CM. 10cm X 5cm.=50SQ.CM
Divide each side by 6, and solve for X.
X will equal 5 cm. Go up and substitute the 5cm. for the value of X.