# A rectangle has dimensions 3x and 5-2x. 1. What is the maximum area of the rectangle? 2. What value of 'x' gives the maximum area?

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### 1 Answer

Area of rectangle;

`A = 3x(5-2x) = 15x-6x^2`

For maximum or minimum area `(dA)/dx = 0`

`(dA)/dx = 15-12x`

When `(dA)/dx = 0`

`15-12x = 0`

`x = 5/4`

If A has a maximum then `(d^2A)/dx^2 < 0` at x = 5/4

`(dA^2)/dx^2 = -12 < 0 `

So A has a maximum.

Maximum `A = 3*5/4(5-2*5/4) = 9.375`

*So the maximum area of the rectangle is 9.375 and it occurs when x = 5/4.*

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