a rectangle athletic field is twice as long as it is wide. If the perimeter of the athletic field is 180 yards, what are it's dimensions?
You need to use the formula of perimeter of rectangle, such that:
`P = 2(L + w)`
`L` represents the length of rectangle
`w` represents the width of rectangle
The problem provides the information that the rectangle athletic field is twice as long as it is wide, hence, translating into equation yields:
`L = 2w`
Replacing 180 for perimeter and `2w` for `L` in equation of perimeter, yields:
`180 = 2(2w + w) => 180 = 2*3w => 180 = 6w => w = 180/6 => w = 30 yards => L = 2*30 => L = 60` yards
Hence, evaluating the dimensions of the rectangle athletic field, under the given conditions, yields `L = 60` yards and `w = 30` yards.
The athletic field is shaped as a rectangle. Its length is twice its width.
Let the length of the field be represented by L and the width is represented by W.
As the length is twice the width, L = 2*W
The perimeter of the field is 2*L + 2*W
2*L + 2*W
= 4*W + 2*W
The perimeter is 180 yards.
6*W = 180
W = 180/6 = 30
The width of the field is 30 yards and the length is 60 yards.