# a rectangle athletic field is twice as long as it is wide. If the perimeter of the athletic field is 180 yards, what are it's dimensions? You need to use the formula of perimeter of rectangle, such that:

`P = 2(L + w)`

`L` represents the length of rectangle

`w` represents the width of rectangle

The problem provides the information that the rectangle athletic field is twice as long as it is wide, hence, translating into...

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You need to use the formula of perimeter of rectangle, such that:

`P = 2(L + w)`

`L` represents the length of rectangle

`w` represents the width of rectangle

The problem provides the information that the rectangle athletic field is twice as long as it is wide, hence, translating into equation yields:

`L = 2w`

Replacing 180 for perimeter and `2w` for `L` in equation of perimeter, yields:

`180 = 2(2w + w) => 180 = 2*3w => 180 = 6w => w = 180/6 => w = 30 yards => L = 2*30 => L = 60` yards

Hence, evaluating the dimensions of the rectangle athletic field, under the given conditions, yields `L = 60` yards and `w = 30` yards.

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