# A real estate agent received a 6% commission on the selling price of a house. If his commission was $8,880, what was the selling price of the house?

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### 3 Answers

The commission of the real estate agent is 6% on the selling price of the house. The commission received is 8880.

Let the selling price be S.

We have 6% of S equal to 8880

=> .06* S = 8880

=> S = 8880/.06

=> S = 148000

**Therefore the selling price is $148,000.**

Let us assume that the selling Price of the house is X.

The real estate agent recieved 6% of the selling price which is 8,880 dollars.

Then we will write: 6% (x) = 8,880

==> (6/100) x = 8880

Let us solve for x.

Let us multiply by 100/6

==> x = 8880 * 100/6

==> x = 148,000 dollars

**Then, the selling price of the house is $148,000**

It is required to find the price of the house.

Rate of commission r = 6% of the house price p.

Let P be the price of the house.

Then the commission at 6% on P is 6% of P = 0.06P. But this commission of 0.06P is said to be equal to $8880.

=> 0.06P = $8880.

=> P/0.06 = $8880/0.06 = $148000.

> P = $148000.

**Therefore the price of the house = $148000.**