Reaction: FeCl2(aq) + Na2CO3(aq) -> FeCO3(s) + 2 NaCl(aq)
If 60.0 ml of 0.500 M FeCl2 is mixed with 50.0 mL of 0.700 M Na2CO3, how many moles (or millimoles) of each ion (Fe 2+, Cl -, Na +, CO3 2-) are added to mixture?
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The reactants dissociate in solution as: FeCl2 ↔ Fe˄2+ + 2Cl˄- and
Na2CO3↔2Na˄+ + CO3˄2-
Number of millimoles of a species is obtained by multiplying molarity with its volume in ml. So, number of millimoles of FeCl2 is 60.0×0.5 = 30, and number of millimoles of Na2CO3 is 50.0×0.7 = 35. From the mode of dissociation of the reactants, number of millimoles of Fe˄2+ added is 60.0×0.5 = 30, number of millimoles of Cl˄- added is 2×60.0×0.5 = 60, number of millimoles of Na˄+ added is 2×50.0×0.7 = 70 and number of millimoles of CO3˄2- added is 50.0×0.7 = 35.
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