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The rate at which water is supplied to the factory given by
Thus volume of the water supplied from 6 AM to 1.00 PM.It is not given to us when t=0 what V= ? ,so we can not solve this as initial value problems.
Thus volume of water supplied to factory from 9.00 AM to 01.00 PM
is 804 cubic m.
The rate at which water is supplied to a factory is given by `V(t) = 3t^2 - 16t + 10` m^3/hour where t = 0 at 6:00 AM.
Assuming t is the no. of hours starting from 6:00 AM,
t=3 at 9 AM and t=7 at 1 PM.
Hence, the volume of water supplied between 9 AM and 1 PM is given by:
`int_3^7 3t^2 - 16t + 10 dt`
Therefore, the volume of water supplied in the given interval of time is 36 m^3.
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