Given that the speed of the plane with the wind = 1500/3 hours.

==> The speed = 1500/3 = 500 mph.

Let (s) be the apeed of the plane in still air.

Letthe speed of the wind be (sw).

==> 500 = s + sw...............(1)

Also, we are given that the speed against the wind = 1500/(3 1/3).

==> 1500/ (10/3) = 1500*3/10 = 450 mph.

==> 450 = s - sw..................(2)

Now we will add equation (1) and (2);

==> 2s = 950

==> s = 950/2 = 475.

**Then, the speed of the plane in still air is 475 mph.**

The airplane covers a distance of 1,500 miles in 3 hours when it flies with the wind and 3 and 1/3 hours when it flies against the wind. We have to find the speed of the plane in still air.

Let the speed of the wind be W and the speed of the airplane be A. Speed is equal to distance/time.

When the airplane travels with the wind, the two speeds are added together.

W + A = 1500/3...(1)

When the airplane travels against the wind, the speed is given by A - W.

A - W = 1500/ (3 + 1/3)...(2)

Now (2) + (1) gives

A - W + W + A = 1500/ (3 + 1/3) + 1500/3

=> 2A = 1500/ (3 + 1/3) + 1500/3

=> 2A = 1500/(10/3) + 1500/3

=> 2A = 150*3 + 500

=> 2A = 450 + 500

=> 2A = 950

=> A = 950/2

=> A = 475

**Therefore the speed of the airplane in still air is 475 miles/hr.**

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