if the random variable z is a standard normal score what is p(-2.00<_z<_+2.00)? how did you find the probabiltyplease show and or explain
The probability for (-2<z<2) = 1-(pr(z<= -2) + pr(z>=2))
This reads 'the probability z is between -2 and 2 equals 1 minus the probability that z is less than or equal to -2 and z is greater than or equal to 2'.
This is because the probability that z is less than or equal to -2, the probability that z is between -2 and 2 and the probability that z is greater than or equal to 2 all sum to one - there are no other possibilities for z.
Now, the normal distribution is symmetric about z=0 so
pr(z>=2) = pr(z<= -2)
This symmetry is very useful when using tables which generally only give you pr(z<=a) for some value a.
Now that we know this we then have that
pr(-2<z<2) = 1-(pr(z<= -2) + pr(z>=2))
= 1- 2*pr(z<=-2)
where Phi is the cumulative distribution function of the normal distribution given in the table. If you look at the value for -2 in the table the probability is 0.023 so
pr(-2<z<2) = 1-2*0.023 = 1- 0.046 = 0.954
You integrate the Normal distribution between -2 and 2. This can't be done in closed form so you would need to use a computer or look up tables.
However, +/-2 standard deviations is a common thing to look at so you should know that this is roughly probability 0.95 (0.954).
On a computer you would do 1-Phi(-2)*2 = 0.954 where Phi is the cdf of the standard Normal distribution ie the probabililty in each tail is roughly 0.025