Formula: `y=Ce^(kt)` where y is the amount of radioactive radium at time t, k is the decay constant, and C is the initial amount of radium
`1/2C=Ce^(k*1599)`
`1/2=e^(k*1599)`
`ln(1/2)=1599klne`
`ln(1/2)=1599k`
`ln(1/2)/1599=k`
`k=-4.3349x10^-4`
`y=Ce^(kt)`
`y=Ce^[(-4.3349x10^-4)(100)]`
`y=.9576C`
Final Answer: 95.76% of radioactive radium is left after 100 years.
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