# Question is to long so i put it in explanation box PLEASE HELP!In a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall with a speed of 14 m/s at an...

Question is to long so i put it in explanation box PLEASE HELP!

In a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall with a speed of 14 m/s at an angle of 24o above the horizontal.**a)** How long does it take for the ball to reach the wall if it is 4.2 m away? - s**b)** How high is the ball when it hits the wall

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a) You should remember the equation that relates the distance, velocity and time such that:

`D = v*t`

The problem provides the velocity and the total distance, hence, you should evaluate the time such that:

`t = D/v`

You need to consider the horizontal component of velocity such that:

`v_x = v cos 24^o`

`t = D/(v*cos 24^o) => t = 4.3/(14*cos 24^o) => t = (4.3 m)/(12.789 m/s)`

`t = 0.33 ` s

**Hence, evaluating the time taken for the ball to hit the wall yields `t = 0.33 s` .**

b) You know that the ball hits the wall after `t = 0.33 s,` hence, using the vertical component of velocity, you may evaluate the height reached by the ball when it hits the wall such that:

`h = v_y*t => h = 14*sin 24^o*0.33`

`h ~~ 1.879 m`

**Hence, evaluating how high is the ball when it hits the wall yields `h ~~ 1.879 m` .**