The diagonal BD separates the quadrilateral into triangles: `Delta` ABD and `Delta` BCD. The sum of the angles of a triangle is equal to 180 degrees.

Two of the angles of `Delta` ABD are 93 degrees and 43 degrees. Subtract from 180 degrees to find the measure of the third angle: 180 - 93 - 43 = 44. The measure of `/_` ABD = 44 degrees.

The angles of `Delta` BCD are (x + 19), (2x + 6), and (3x + 5). Their sum is 180 degrees. Write this as an equation and solve for x.

(x + 19) + (2x + 6) + (3x + 5) = 180

6x + 30 = 180

6x = 150

x = 25

Substitute 25 in for x to find the measures of the angles of `Delta` BCD.

`/_` BDC = x + 19 = 25 + 19 = 44 degrees

`/_` DBC = 2x + 6 = 2 * 25 + 6 = 56 degrees

`/_` BCD = 3x + 5 = 3 * 25 + 5 = 80 degrees

The diagonal BD acts as a transversal, causing `/_` ABD and `` BDC to be alternate interior angles.

`/_` ABD = 44 degrees

`/_` BDC = 44 degrees

Therefore `/_` ABD = `/_` BDC.

When alternate interior angles are congruent, the opposite sides are parallel. Therefore, side AB is parallel to side CD.

However, the shape is not a parallelogram because in a parallelogram, opposite angles are congruent.

`/_` A = 93 degrees and `/_` C = 80 degrees. `/_` A `!=` `/_` C

`` B = 100 degrees and `/_` D = 87 degrees. `/_` B `` `` D

Quadrilateral ABCD is not a parallelogram (2 pairs of parallel sides). It is a trapezoid (1 pair of parallel sides).

**Answer: AB is parallel to DC.**