Quadratic Functions: Express Curve in its equation in the form of f(x)=a(x+p)^2+q
How To Express Curve in its equation in the form of f(x)=a(x+p)^2+q
The curve: http://i44.tinypic.com/9k4aah.jpg
I know that f(x)=ax^2 + bx + c = a(x+p)^2+q,the equation of its symmetry is x= -p = -(b/2a), but how to solve this question?
(-p,q) is the vertex so we have
Since the y-intercept is 7, we use the point (0,7) to find a:
So we have