`h(t) = -4.9t^2+ 540t + 25`

When the height is 0;

`-4.9t^2+ 540t + 25 = 0`

The solution for above quadratic equation is given by;

`t = ((-540)+-sqrt(540^2-4*(-4.9)*25))/(2*(-4.9))`

`t = -0.0463` OR `t = 110.25`

Usually time is a positive component. So t = -0.0463 not acceptable.

*So the rocket height is 0 when the time is 110.25 seconds.*

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