quadraticWhat is the discriminant of quadratic equation x^2+11x+121=x+96?
The discriminant of an equation ax^2 + bx + c = 0 is b^2 - 4ac
Here we have x^2+11x+121=x+96
=> x^2 + 10x +25 = 0
b^2 - 4ac = 100 - 100 = 0
The discriminant is 0.
`x^2+11x+121=x+96` combine the like terms
`x^2+10x+25=0 ` to find the discminant use the formula `b^2-4ac`
`a=1` `b=10 ` `c=25 ` plug it in
`10^2-4(1)(25) ` simplify
`100-100` make an equation
`100-100=0` so the discriminant is 0, this means the problem has 1 real solution
Before determining the discriminant, we'll move all terms to the left side:
x^2+11x+121-x-96 = 0
We'll combine like terms:
x^2 + 10x + 25 = 0
We'll write the formula of discriminant:
delta = b^2 - 4ac
We'll identify the coefficients a,b,c:
a = 1, b = 10 , c = 25
delta = 100 - 4*25
delta = 100 - 100
delta = 0
The discriminant of quadratic equation is delta = 0.