Only in the **uniform circular motion** the force is directed towards the center of the circle, and thus is not doing work. If the motion is non uniform there will be two forces acting on the mass. First force is towards the center and its **instantaneous** value is

`F_n =m*V^2/R`

This normal force is not doing any work (because it is perpendicular to the instant speed).

The second force is tangential to the trajectory and its value is

`F_t = m*a =m*dV/dt =m*(6-2t)`

**This force is doing work because is parallel to the speed.**

The work done is

`W = F_t(1)*v(1) =1*(6-2)*(6-1) =20J`

**Therefore the correct answer is a) 20 J**

**Further Reading**

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