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If we take the limit directly, we will have an indeterminate form.
`lim_(x->pi/2) = (2(pi/2) - pi)/(cos(pi/2)) = (pi - pi)/0 = 0/0.`
So, we will apply L'hospital Rule here.
Take the derivative of top and bottom separately first.
So, we will have:
`lim_(x->pi/2) = 2/(-sin(pi/2)) = 2/-(1) = -2.`
Hence, final answer is -2.
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