# Put in algebraic equation: The difference of 3 times a number y and 2 equals 19.   I can't figure this out to help my daughter. Thanks

## Expert Answers 3y-2=19

3y-2+2=19+2

3y=21

3y/3=21/3

y=7

Approved by eNotes Editorial Team The concept of three times a number y and two equals 19 is simply written as

3y+2 = 19

To find the solution to this equasion you simply subtract 2 from each side which leaves you with 3y=17 .  At this juncture you divide each side by 3 and that gives you Y=17/3

The soultion would be  Y= 5 2/3

Approved by eNotes Editorial Team 3y-19=2

It is worded a little strangely, but what they are saying is that 3 times the unknown number is 19 more than 2.

Add 19 to each side of the equation; you then have 3y=21.

Divide each side by 3, and y=7

You could also look at it as 3y-2=19; add 2 to each side, and once again you have 3y=21

Approved by eNotes Editorial Team

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