put 3x-9y=9 in slope intercept form then state y-intercept and slope of the line...find the line that is perpendicular to this line and passes thru the point(2,7)thank you for your help
3x -9y = 9
First we will rewrite the equation as a function of x.
==> 3x -9 = 9y
==> 9y = 3x -9
Now we will divide by 9.
==> y= (1/3) x - 1 ( Slope-intercept form)
==> y-intercept is (0, -1)
The slope is m= 1/3
==> Slope of perpendicular line is -3
Given the point (2,7) passes through the perpendicular line.
==> y-y1 = m (x-x1)
==> y -7 = -3 (x-2)
==> y= -3x +6 +7
==> y= -3x +13 ( equation of perpendicular line)
3x - 9y = 9
Slope intercept form is y = mx + b. To change what you have into slope intercept, just solve for y.
x - 3y = 3 (Divide out the 3s)
3y = x - 3 (Isolate y term)
y = (1/3)x - 1 (solve for y)
We know the slope is 1/3. A line perpendicular to this one would have a slope of -3. We want that line to pass through (2,7). We have a point and a slope so lets put that into point-slope form and we're done!
y - 7 = -3(x - 2)