Prove that `sec^4(x)-tan^4(x)=1+tan^2(x)` .

Expert Answers info

jeew-m eNotes educator | Certified Educator

calendarEducator since 2012

write1,657 answers

starTop subjects are Math, Science, and Social Sciences

We know sec^2x = 1+tan^2x and (x^2-y^2)=(x-y)(x+y)

 

sec^4x-tan^4x

=(sec^2x-tan^2x)(sec^2x+tan^2x)

=(1+tan^2x-tan2^x)(1+tan^2x+tan^2x)

=(1)(1+2tan^2x)

= (1+2tan^2x)

 

Your question should be modfied as;

sec^4x-tan^4x

check Approved by eNotes Editorial

Rylan Hills eNotes educator | Certified Educator

calendarEducator since 2010

write12,544 answers

starTop subjects are Math, Science, and Business

The identity `sec^4 x - tan^4 x = 1 + tan^2 x` has to be proved.

`sec^4 x - tan^4 x`

=> `(sec^2x - tan^2x)(sec^2x + tan^2x)`

=> `(1/(cos^2x) - (sin^2x)/(cos^2x))(1/(cos^2x) + (sin^2x)/(cos^2x))`

=> `((1 - sin^2x)/(cos^2x))((1 + sin^2x)/(cos^2x))`

=> `((cos^2x)/(cos^2x))((1 + sin^2x)/(cos^2x))`

=> `(1 + sin^2x)/(cos^2x)`

=> `sec^2x + tan^2x`

=> `1 + tan^2x + tan^2x`

=> `1 + 2*tan^2x`

It is seen that `sec^4 x - tan^4 x = 1 + tan^2 x` is not an identity, instead: `sec^4x - tan^4x = 1 + 2*tan^2x`

check Approved by eNotes Editorial