Prove that the limit of function f(x) is ln5, if function f(x) is given by f(x) =(5^x-5)/(x-1), x->0.

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The value of the function given f(x) = (5^x-5)/(x-1), for x --> 0 can be arrived at by substituting the value of x = 0 in the expression for the function f(x) = (5^x-5)/(x-1)

=> (5^0 - 5)/( 0 - 1)

=> ( 1 - 5) / (0 - 1)

=> +4

The required value of lim x-->0 [ (5^x-5)/(x-1)] = +4 not ln 5.

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