The product of two positive numbers is 124. If one of the numbers is x, the other number is `124/x` . The sum of the two numbers is `S = x + 124/x`
The first derivative of S is `S' = 1 - 124/x^2`
Solving S' = 0
=> `1 - 124/x^2 = 0`
=> `x = sqrt 124`
At `x = sqrt 124` , S'' is positive. This indicates that the value of S is minimum when `x = sqrt 124` . The maximum value that S can take on is infinity.
The maximum value of the sum of the two numbers is infinity.
See eNotes Ad-Free
Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.
Already a member? Log in here.