The probability that it rains is P(R) = 0.5 and the probability of heavy winds is P(W) = 0.6. From this we can derive that the probability of it not raining is P(nR) = 1 - P(R) = 1 - 0.5 = 0.5 and the probability of heavy winds not...

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The probability that it rains is P(R) = 0.5 and the probability of heavy winds is P(W) = 0.6. From this we can derive that the probability of it not raining is P(nR) = 1 - P(R) = 1 - 0.5 = 0.5 and the probability of heavy winds not occurring is P(nW) = 1 - P(W) = 1 - 0.6 = 0.4.

The probability of both events taking place together is P(W & R) = 0.2. This gives the probability of neither of the events taking place together as P(nR & nW) = 1 - 0.2 = 0.8.

The probability of it no rain as well as no heavy winds is P(nW) + P(nR) - P(nR & nW) = 0.5 + 0.4 - 0.8 = 0.1

**There is a 10% probability that it neither rains nor are there heavy winds.**