If in a small poker party it is required that guest bring either a bag of M&M's or a bag of Cereal, what is the answer to the following:a) How many M&M's are expected if there is a 50%...

If in a small poker party it is required that guest bring either a bag of M&M's or a bag of Cereal, what is the answer to the following:

a) How many M&M's are expected if there is a 50% chance that the guests bring M&M's?

b) What is the probability that there at least 2 bags of cereal?

Asked on by juno60

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justaguide | College Teacher | (Level 2) Distinguished Educator

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In the poker party guests are required to bring either a bag of M&Ms or a bag of Cereal.

It is given that there is a 50% chance that the guests bring M&Ms but the number of guests arriving is not mentioned. This does not allow one to calculate the number of M&Ms that can be expected though if there are a total of N guests coming to the party, there is a high probability that the number of M&Ms is N/2.

The same problem arises with estimating the probability that there are at least 2 bags of cereal. Though it can be said that as the number of guests increases, there is an increase in the probability that at least 2 bags of cereal are brought in by them.

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