preparation of elemental phosphorus can be done as follows:
2Ca3(PO4)2 + 6SiO2 --> 6CaSiO3 + P4O10
P4O10 + 10C --> P4 + 10CO
calculate the % of Ca3(PO4)2 initially present in the sample if 307kg of phosphate rock yields 42.5kg of elemental P4
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First, you have to ensure that the equations are balanced. It seems that both of the equations are balanced. Next, you can combine the two equations to form a single equation to show the relationship of the compounds. By doing so, you will have the chemical equation:
`2Ca_3(PO_4)_2 + 6SiO_2 + 10 C -> 6CaSiO_3 + P_4O_10 + P_4 + 10 CO`
Next, we do some stoichiometric procedure for the determination of the mass of `Ca_3(PO_4)_2` and eventually the percent mass of it in the sample.
`= 212, 802.001 grams of Ca_3(PO_4)_2`
`= 212.80 kg of Ca_3(PO_4)_2`
To calculate the percent `Ca_3(PO_4)_2` in the sample, we divide it by the total amount of sample multiplied by 100.
`% Ca_3(PO_4)_2 = (Mass Ca_3(PO_4)_2)/(mass of sampl e) * 100`
` ` `% Ca_3(PO_4)_2= (212.80 kg)/(307 kg) * 100`
`% Ca_3(PO_4)_2 = 69.3%` --> final answer
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