# A power lifter was able to dead lift 237.5 kg. If the weights traveled a total distance of 1.25m, how much work did he do.

*print*Print*list*Cite

The power lifter lifts a mass of 237.5 kg. The downward force exerted by the mass is given by F = m*g = 237.5*9.8 = 2327.5 N

To lift the mass the power lifter has to exert an equal force on the mass that is being lifted. This is equal to 2327.5 N. The mass is lifted to a height of 1.25 m.

Work done is equal to the product of the force applied and the distance the through which the force is applied. In the problem the work done is equal to 1.25*2327.5 = 2909.375 J

**The work done by the power lifter to lift the mass of 237.5 kg to a height of 1.25 m is 2909.375 J**

WE KNOW THAT PORTER LIFTED A THE **OBJECT AGAINST THE GRAVITATION **

♦ THEREFORE IT IS SAID TO BE** GRAVITATIONAL POTENTIAL ENERGY**

♦** WORK DONE BY THE PORTER IN RAISING THE OBJECT = m*g*h**

= 237.5 * 1.5 * 9.8 (acceleration due to gravity)

**= 2909.37 J **