the position fo an object at any time is given by the equation s(t)=4.t^3-9.t+13 find the equation of its velocity and its acceleration v(t)= a(t)= its velocity is giveb by v(t) its acceleration is given y a(t)

Expert Answers

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The derivative of position function gives the velocity function.

`v(t) = (ds(t))/dt`

The derivative of the velocity function gives acceleration function.

`a(t) = (dv(t))/dt`

 

`s(t)=4t^3-9t+13`

`v(t) = (ds(t))/dt`

`v(t) = 12t^2-9`

 

`a(t) = (dv(t))/dt`

`a(t) = 24t`

 

So;

Velocity function `v(t) = 12t^2-9`

Acceleration function `a(t) = 24t`

 

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