The population of San Francisco is 750,000 in an area of 49 square miles. What is the population density in San Francisco? Express your answer in the people per acre. (1 mi^2 = 640 acres) 

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intheknow's profile pic

intheknow | (Level 2) Adjunct Educator

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San Francisco is the most dense of large cities (population > 200,000) in California, and is second to New York nationally.  The population numbers given most reflect the city of San Francisco in the 1990s.  According to the Office of Financial Management, the most common unit of population density is expressed as number of people per square mile of land area,  with the land area measurements excluding any bodies of water located within.  Population density is used to determine how crowded a piece of land (or a city) is which is helpful when the goverment evaluates what services are needed in a given area.

With the given numbers, the calculation to achieve population density expressed in people per acre looks like this:

750,000 people / 49 sq. mi. = 15,306 people/ sq. mi.

15,306 people / sq. mi. X 1 sq. mi. / 640 Ac = 23.92 people / acre

Therfore the population density of San Francisco at this given time is 23.92 persons per acre 

aruv's profile pic

aruv | High School Teacher | (Level 2) Valedictorian

Posted on

1 sq. mile = 640 acers

49 sq. miles = 49 x 640 acers

                  =31360 acers

Area of the San Francisco =31360 acres

Population of San Francisco = 750,000

Since

Population density = (population)/(area) 

Thus

Population density of San Francisco=750000/31360 peoples/acre

= 24 peoples/acre  (approx.)

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