In a population of rabbits, there are 496 black rabbits and 27 white rabbits. Fur color is determined by a pair of alleles where "B" is the dominant allele which produces black fur, and "b" the recessive allele which produces white fur. The frequency of the dominant allele for B is 0.8. What is the frequency of the black fur phenotype in the population (the population is in Hardy-Weinberg Equilibrium)? 

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Since the population is in Hardy-Weinberg equilibrium, the dominant allele displays complete dominance. This means that rabbits with black fur have a genotype of either BB or Bb. Since the numbers of both black and white rabbits are given, we can easily calculate the frequency of the black fur phenotype.

Black fur phenotype frequency = number of black rabbits/(number of black rabbits + number of white rabbits)

                                            = 496/(496 + 27)

                                            = 496/523


(The entire section contains 228 words.)

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